The bent rod in Fig. a is supported at A by a journal bearing, at D bya ball-and-socket joint, and at B by means of cable BC. Using onlyone equilibrium equation, obtain a direct solution for the tension incable BC. The bearing at A is capable of exerting force componentsonly in the z and y directions since it is properly aligned on the shaft.In other words, no couple moments are required at this support.1mB0.5 m.Free-Body Diagram. As shown in Fig. b, there are six unknowns0.5 mDEquations of Equilibrium. The cable tension Tg may be obtaineddirectly by summing moments about an axis that passes throughpoints D and A. Why?100 kg(a)Since the moment arms from the axis to Tg and W are easy to obtain,we can determine this result using a scalar analysis. As shown,Fig. bEMPA = 0; T(1 m sin 45°) - 981 N(0.5 m sin 45°) = 0T = 490.5 NB.45°-0.5 m W = 981 NDD,0.5 mD,D,(b)

The bent rod in Fig. a is supported at A by a journal bearing, at D by a ball-and-socket joint, and at B by means of cable BC. Using only one equilibrium equation, obtain a direct solution for the tension in cable BC. The bearing at A is capable of exerting force components only in the z and y directions since it is properly aligned on the shaft. In other words, no couple moments are required at this support. B. 0.5 m .Free-Body Diagram. As shown in Fig. b, there are six unknowns 0.5 m D Equations of Equilibrium. The cable tension Tg may be obtained directly by summing moments about an axis that passes through points D and A. Why? 100 kg (a) Since the moment arms from the axis to Tg and W are easy to obtain, we can determine this result using a scalar analysis. As shown,Fig. b EMDA = 0; T(1 m sin 45°) - 981 N(0.5 m sin 45°) = 0 T = 490.5 N B. 45 0.5 m W- 981 NE 0.5 m D, (b)

The bent rod in Fig. a is supported at A by a journal bearing, at D by a ball-and-socket joint, and at B by means of cable BC. Using only one equilibrium equation, obtain a direct solution for the tension in cable BC. The bearing at A is capable of exerting force components only in the z and y directions since it is properly aligned on the shaft. In other words, no couple moments are required at this support. B. 0.5 m .Free-Body Diagram. As shown in Fig. b, there are six unknowns 0.5 m D Equations of Equilibrium. The cable tension Tg may be obtained directly by summing moments about an axis that passes through points D and A. Why? 100 kg (a) Since the moment arms from the axis to Tg and W are easy to obtain, we can determine this result using a scalar analysis. As shown,Fig. b EMDA = 0; T(1 m sin 45°) - 981 N(0.5 m sin 45°) = 0 T = 490.5 N B. 45 0.5 m W- 981 NE 0.5 m D, (b)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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