The block brake shown below is set by a spring that produces a force S on each arm equal to 682 lb. The wheel diameter is 14 in., and the angle of contact for each block is 110°. Using 0.40 as a value of the coefficient of friction between the drum and lining, determine the maximum torque in foot-pounds that the brake is capable of absorbing. S + S 1/2" 1/2"

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter7: Dry Friction
Section: Chapter Questions
Problem 7.55P: A wedge is used to prop up the 6000-lb block of marble. The wedge angle is =30, and the angle of...
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The block brake shown below is set by a spring that produces a force S on each arm equal to 682 lb. The
wheel diameter is 14 in., and the angle of contact for each block is 110°. Using 0.40 as a value of the
coefficient of friction between the drum and lining, determine the maximum torque in foot-pounds that
the brake is capable of absorbing.
S
+
S
1/2" 1/2"
Transcribed Image Text:The block brake shown below is set by a spring that produces a force S on each arm equal to 682 lb. The wheel diameter is 14 in., and the angle of contact for each block is 110°. Using 0.40 as a value of the coefficient of friction between the drum and lining, determine the maximum torque in foot-pounds that the brake is capable of absorbing. S + S 1/2" 1/2"
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can you please explain more and draw about summation of forces on this problem

= req
Considering
EM
↑
-
= S(a+b)
s(a+b)
s(a+b)
O
12
static equilibrium of the lever,
sx (a+b) + fxr
N =
S
=
s (a + b)
2 (1-Meg)
aximum torque, T = fr
Nr-fr.
Nr - Peq
Nr (1-Peq)
=
Nr
Nr
Peq
NXr
682 x (9½ +81
Transcribed Image Text:= req Considering EM ↑ - = S(a+b) s(a+b) s(a+b) O 12 static equilibrium of the lever, sx (a+b) + fxr N = S = s (a + b) 2 (1-Meg) aximum torque, T = fr Nr-fr. Nr - Peq Nr (1-Peq) = Nr Nr Peq NXr 682 x (9½ +81
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