The circle of radius 1 centered at (-3, 4,1) and lying in a plane parallel to the yz-axis is a) (y-2)²+(2-1)² = 1 b) x² = 11 c) x = 1 d) (z-y)²+(y-1)² = -1

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A: Here we have to determine the integration technique to solve the given integration. =∫5dx3+x2

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A: We have to find the point where tangent line is perpendicular to the line 3x+9y=4.

Q: 11 lim 348 n=0 tan ²¹ (-1) + tan²¹²¹ (1) - tan¹ (2n+1) - tan²¹ (2n + 3)] ??

A: To explain the circled part.

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A: To find the intercepts and the vertical asymptote of the following rational function.fx=x2-2x-3x-4

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A: using the simpson's method ∫01xdx for n=4.

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Q: 22

A: We will solve the problem

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A: Given, g(2)=3 , g'(2)=-2, h(2)=-1 , h'(2)=5, f(x)=g(x)h(x)

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A: Given that f and g are continuous function on [a,b].

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A: Since you have posted multiple question in this question which are not interlinked so i have solved…

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A: We need to find f inverse of (g) and show it is a coset of ker(f).

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A: We need to use sine law.

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A: We have to find the domain range and asymptote of the function.

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A: a)2  b) -2  c) -4

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A: We have to find the solution

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A: Option E is not correct .

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A: Topic = Limits

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A: The Simpson's 1/3 rule for integration is given by, ∫ab f(x)dx≈Δx3f(x0)+4f(x1)+2f(x2)+4f(x3)+2f(x4)+…

Q: please show step by step solution on how to get the circled part with complete explanation

A: The given integral:∫x2+2x-2x2-2x+2dx

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A: Solution is done in step 2

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A: Application of differential

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Q: Show

A: Please refer to the image below

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A: This question is related to Functions, we will solve it using given information.

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A: Area of surface is evaluated.

Q: If f is continuous on [a,b], then [a,b], then A) True B) False [ f(x)dx = πf f(x) dx

A: