The common tangent CD of a reversed curve is 280.50 m and has an azimuth of 312-29. BC is a tangent of the first curve whose azimuth is 252*45'. DE is a tangent of the second curve whose azimuth is 218-13. The radius of the first curve is 180m. P.I. is at station 16+523.37. B is at P.C. and E is at P.T. What is the stationing of P..C.?
The common tangent CD of a reversed curve is 280.50 m and has an azimuth of 312-29. BC is a tangent of the first curve whose azimuth is 252*45'. DE is a tangent of the second curve whose azimuth is 218-13. The radius of the first curve is 180m. P.I. is at station 16+523.37. B is at P.C. and E is at P.T. What is the stationing of P..C.?
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![The common tangent CD of a reversed curve is 280.50 m and has an azimuth of 312-29. BC is a tangent of the first curve whose azimuth is 252*45'. DE is a
tangent of the second curve whose azimuth is 218-13. The radius of the first curve is 180m. P.I. is at station 16+523.37. B is at P.C. and E is at P.T. What is the
stationing of P.C.?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F95994bef-7c9b-4470-ac5e-03460ea91623%2F1582c33d-8c58-4af9-9c59-339a8cefb38d%2Fry2nj8o_processed.png&w=3840&q=75)
Transcribed Image Text:The common tangent CD of a reversed curve is 280.50 m and has an azimuth of 312-29. BC is a tangent of the first curve whose azimuth is 252*45'. DE is a
tangent of the second curve whose azimuth is 218-13. The radius of the first curve is 180m. P.I. is at station 16+523.37. B is at P.C. and E is at P.T. What is the
stationing of P.C.?
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