The component of the current due to the voltage source ijis cos(2t + 1 ) A. The component of the current due to the current source is i2 | cos(2t + 1 °)) A. The value of ix=| cos(2t+ | ) A.

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Using the superposition principle, find ix in the circuit given below, where R= 5 0. Please report your answer so the magnitude is
positive and all angles are in the range of negative 180 degrees to positive 180 degrees.
R
10cos(2t + 10°) A
4 H
20cos(2t – 60°) V
The component of the current due to the voltage source ijis
|cos(2t+
) A.
The component of the current due to the current source is i2
cos(2t+
| °)) A.
The value of ix=
|cos(2t+
) A.
ll
Transcribed Image Text:Using the superposition principle, find ix in the circuit given below, where R= 5 0. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. R 10cos(2t + 10°) A 4 H 20cos(2t – 60°) V The component of the current due to the voltage source ijis |cos(2t+ ) A. The component of the current due to the current source is i2 cos(2t+ | °)) A. The value of ix= |cos(2t+ ) A. ll
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