The crystalline lens of the human eye is a double- convex lens made of material having an index of refraction of 1.44 (although this varies). Its focal length in air is about 8.00 mm, which also varies. We shall assume that the radii of curvature of its two surfaces have the same magnitude. (Note: The results obtained in the parts A, B and C are not strictly accurate, because the lens is embedded in fluids having refractive indexes different from that of air.) Find the radii of curvature of this lens. R = ΜΕ ΑΣΦ Submit Request Answer Part B ? mm If an object 10.0 cm tall is placed 33.0 cm from the eye lens, where would the lens focus it? ΜΕ ΑΣΦ ? s' = Submit Request Answer Part C How tall would the image be? Π ΑΣΦ 3= Submit Request Answer ? mm mm

The crystalline lens of the human eye is a double- convex lens made of material having an index of refraction of 1.44 (although this varies). Its focal length in air is about 8.00 mm, which also varies. We shall assume that the radii of curvature of its two surfaces have the same magnitude. (Note: The results obtained in the parts A, B and C are not strictly accurate, because the lens is embedded in fluids having refractive indexes different from that of air.) Find the radii of curvature of this lens. R = ΜΕ ΑΣΦ Submit Request Answer Part B ? mm If an object 10.0 cm tall is placed 33.0 cm from the eye lens, where would the lens focus it? ΜΕ ΑΣΦ ? s' = Submit Request Answer Part C How tall would the image be? Π ΑΣΦ 3= Submit Request Answer ? mm mm