*** The definite integral representing the volume of solid generated when the areain the first quadrant bounded by y= x2 + 4 and y=2x² is revolved about the x - axisusing a vertical strip is equal to(AV=2n| (4x- x³)dx(B+= 1[ (3x² + 4)²dx(Dnone of theseE)V= Tn (8x2 - 3x* + 16)ax

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*** The definite integral representing the volume of solid generated when the area in the first quadrant bounded by y= x² + 4 and y= 2x² is revolved about the x – axis using a vertical strip is equal to A 2(4x-x³)dx V=2n 0. V= T .2 | (3x²+4)²dx V= T B)

*** The definite integral representing the volume of solid generated when the area in the first quadrant bounded by y= x² + 4 and y= 2x² is revolved about the x – axis using a vertical strip is equal to A 2(4x-x³)dx V=2n 0. V= T .2 | (3x²+4)²dx V= T B)

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

ChapterA: Appendix

SectionA.2: Geometric Constructions

Problem 10P: A soda can has a volume of 25 cubic inches. Let x denote its radius and h its height, both in...

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Question

*** The definite integral representing the volume of solid generated when the area
in the first quadrant bounded by y= x2 + 4 and y=2x² is revolved about the x - axis
using a vertical strip is equal to
(A
V=2n| (4x- x³)dx
(B
+
= 1[ (3x² + 4)²dx
(D
none of these
E)
V= T
n (8x2 - 3x* + 16)ax

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