Needed urgently...use the formula list for solving the ques...solve it asap The demand in a water distribution system averages 15 cfs. What is the total annual demand in acrefeet? Water BoardsUNITS AND CONVERSION FACTORS1 cubic foot of water weighs 62.3832 lb1 gallon of water weighs 8.34 lb1 liter of water weighs 1,000 gmState Water Resources Control Board1 mg/L = 1 part per million (ppm)1% = 10,000 ppmft²= square feet and ft² = cubic feet1 mile = 5,280 feet (ft)1 yd³=27ft² and 1 yard = 3 feet1 acre (a) = 43,560 square feet (ft²)1 acre foot = 325,851 gallons1 cubic foot (ft³) = 7.48 gallons (gal)1 gal = 3.785 liters (L)1 L = 1,000 milliliters (ml)1 pound (lb) = 454 grams (gm)1 lb = 7,000 grains (gr)1 grain per gallon (gpg) = 17.1 mg/L1 gm = 1,000 milligrams (mg)1 day = 24 hr = 1,440 min = 86,400 sec1,000,000 gal/day + 86,400 sec/day+ 7.48 gal/cu ft= 1.55 cu ft/sec/MGDCHLORINATIONDosage, mg/l = (Demand, mg/l) + (Residual, mg/l)(Gas) lbs = Vol, MG x ppm or mg/L x 8.34 lbs/galHTH Solid (lbs).(Vol. MG) x (ppm or mg/L) x 8.34 lbs/gal(% Strength / 100)Liquid (gal) = (Vol. MG) x (ppm or mg/L) x 8.34 lbs/gal(% Strength /100) x Chemical Wt. (lbs/gal)PRESSUREPSI (Head, ft.)2.31ft./psilbs Force= (0.785) (D, ft.) x 144 in²ft² x PSI.PSI = Head, ft x 0.433 PSL.VOLUMERectangular Basin, Volume, gal =(Length, ft) x (Width, ft) x (Height, ft) x 7.48 gallcu.ftCylinder, Volume, gal =(0.785) x (Dia, ft) x (Height, Depth, or Length in ft) x 7.48 galitTime, Hrs. =Supply, Hrs. =MATTHEW ROQUEZVolume, gallons(Pumping Rate, GPM, x 60 Min/Hr)Storage Volume, Gals(Flow In, GPM - Flow Out, GPM) x 60 Min/Hr)SOLUTIONSLbs/Gal= (Solution %) x 8.34 Ibs/gal x Specific Gravity100% of Chemical =in SolutionGPD =Lbs Chemical =Spectic Gravity x 8.34 lbsgallons x Solution(gal)Specific Gravity = Chemical Wt. (lbs/gal)8.34 (lbs/gal)GPD =TECTIN(Dry Chemical, lbs) x 100(Dry Wt. Chemical, lbs)+(Water, lbs)(MGD) x (ppm or mg/L) x 8.34 lbs/gal(% purity) x Chemical Wt. (lbs/gal)(Feed, ml/min. x 1,440 min/day)(1,000 ml/Lx 3.785 Ligal)Two-Normal Equations:a) C₁V₁= C₂V₂b)C₁V₁+C₂V₂=C3V3C = Concentration V = Volume9-9Q = Flow1 horsepower (Hp) = 746 watts = 0.746 kw = 3,960 gal/min/tWater Hp = (GPM) x (Total Head.ft)(3,960 gal/min/ft)Brake HpMotor Hp =(GPM) x (Total Head.ft)(3,960) x (Pump % Efficiency)(GPM) x (Total Head.ft)(3,960) x Pump % Eff. x Motor % Eff."Wire-to-Water" Efficiency(Motor, % Efficiency x Pump % Eficiency)Cost, $ =(Hp) x (0.746 Kw/Hp) x (Operating Hrs.) x cents/kw-HrFlow. velocity, areaQ=AxVQuantity = Area x VelocityFlow (ft³/sec) = Area(ft³) x Velocity (ft/sec)MGD x 1.55 cuft/sec/MGD785 xpipe diameter ft x pipe diameter ftGeneral($) Cost/dayRemoval, Percent=4mA=0Specific Capacity, GPM/ttIbs/day x ($) Costlb(In-Out) x 100In- cu frec-tisec= sqft=Well Yield, GPMDrawdown, ft.Gals/Day = (Population) x (Gals/Capita/Day)GPD = (Meter Read 2 - Meter Read 1)(Number of Days)Volume, Gals = GPM x Time, minutesSCADA= 4 mA to 20 mA analog signal(live signal mA-4 mA offset) x process unit and range(16 mA span)20mA full-range

Question

Needed urgently...use the formula list for solving the ques...solve it asap The demand in a water distribution system averages 15 cfs. What is the total annual demand in acrefeet? Water BoardsUNITS AND CONVERSION FACTORS1 cubic foot of water weighs 62.3832 lb1 gallon of water weighs 8.34 lb1 liter of water weighs 1,000 gmState Water Resources Control Board1 mg/L = 1 part per million (ppm)1% = 10,000 ppmft²= square feet and ft² = cubic feet1 mile = 5,280 feet (ft)1 yd³=27ft² and 1 yard = 3 feet1 acre (a) = 43,560 square feet (ft²)1 acre foot = 325,851 gallons1 cubic foot (ft³) = 7.48 gallons (gal)1 gal = 3.785 liters (L)1 L = 1,000 milliliters (ml)1 pound (lb) = 454 grams (gm)1 lb = 7,000 grains (gr)1 grain per gallon (gpg) = 17.1 mg/L1 gm = 1,000 milligrams (mg)1 day = 24 hr = 1,440 min = 86,400 sec1,000,000 gal/day + 86,400 sec/day+ 7.48 gal/cu ft= 1.55 cu ft/sec/MGDCHLORINATIONDosage, mg/l = (Demand, mg/l) + (Residual, mg/l)(Gas) lbs = Vol, MG x ppm or mg/L x 8.34 lbs/galHTH Solid (lbs).(Vol. MG) x (ppm or mg/L) x 8.34 lbs/gal(% Strength / 100)Liquid (gal) = (Vol. MG) x (ppm or mg/L) x 8.34 lbs/gal(% Strength /100) x Chemical Wt. (lbs/gal)PRESSUREPSI (Head, ft.)2.31ft./psilbs Force= (0.785) (D, ft.) x 144 in²ft² x PSI.PSI = Head, ft x 0.433 PSL.VOLUMERectangular Basin, Volume, gal =(Length, ft) x (Width, ft) x (Height, ft) x 7.48 gallcu.ftCylinder, Volume, gal =(0.785) x (Dia, ft) x (Height, Depth, or Length in ft) x 7.48 galitTime, Hrs. =Supply, Hrs. =MATTHEW ROQUEZVolume, gallons(Pumping Rate, GPM, x 60 Min/Hr)Storage Volume, Gals(Flow In, GPM - Flow Out, GPM) x 60 Min/Hr)SOLUTIONSLbs/Gal= (Solution %) x 8.34 Ibs/gal x Specific Gravity100% of Chemical =in SolutionGPD =Lbs Chemical =Spectic Gravity x 8.34 lbsgallons x Solution(gal)Specific Gravity = Chemical Wt. (lbs/gal)8.34 (lbs/gal)GPD =TECTIN(Dry Chemical, lbs) x 100(Dry Wt. Chemical, lbs)+(Water, lbs)(MGD) x (ppm or mg/L) x 8.34 lbs/gal(% purity) x Chemical Wt. (lbs/gal)(Feed, ml/min. x 1,440 min/day)(1,000 ml/Lx 3.785 Ligal)Two-Normal Equations:a) C₁V₁= C₂V₂b)C₁V₁+C₂V₂=C3V3C = Concentration V = Volume9-9Q = Flow1 horsepower (Hp) = 746 watts = 0.746 kw = 3,960 gal/min/tWater Hp = (GPM) x (Total Head.ft)(3,960 gal/min/ft)Brake HpMotor Hp =(GPM) x (Total Head.ft)(3,960) x (Pump % Efficiency)(GPM) x (Total Head.ft)(3,960) x Pump % Eff. x Motor % Eff.&#34;Wire-to-Water&#34; Efficiency(Motor, % Efficiency x Pump % Eficiency)Cost, $ =(Hp) x (0.746 Kw/Hp) x (Operating Hrs.) x cents/kw-HrFlow. velocity, areaQ=AxVQuantity = Area x VelocityFlow (ft³/sec) = Area(ft³) x Velocity (ft/sec)MGD x 1.55 cuft/sec/MGD785 xpipe diameter ft x pipe diameter ftGeneral($) Cost/dayRemoval, Percent=4mA=0Specific Capacity, GPM/ttIbs/day x ($) Costlb(In-Out) x 100In- cu frec-tisec= sqft=Well Yield, GPMDrawdown, ft.Gals/Day = (Population) x (Gals/Capita/Day)GPD = (Meter Read 2 - Meter Read 1)(Number of Days)Volume, Gals = GPM x Time, minutesSCADA= 4 mA to 20 mA analog signal(live signal mA-4 mA offset) x process unit and range(16 mA span)20mA full-range

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We are given
Average demand in water distribution system = 15 cfs
cfs = cubic feet/sec
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The demand in a water distribution system averages 15 cfs. What is the total annual demand in acre feet?