The derivative of the function f is defined by f'(x) = x? – 5x + 5 cos (3x? – 3x). If ƒ(-2) = –4, what is the absolute maximum value of the function f on the closed interval [-2, 3]? You may use a calculator and round your answer to the nearest thousandth.

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Q: 19.What is the derivative with respect to a of f(x) = 4-32 3z+2 4x-3

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Q: What is the derivative of the function h(x) = ((4x^2-4)/(cos(x)))^8

A: We have to find the derivative of ((4x^2-4)/(cos(x)))^8 = 4^8(x^2-1) sec^8(x)= 65536(x^2-1)sec^8(x)