The diagram below is a top-down view of two children pulling a 11.6-kg sled along the snow. The first child exerts a force of F1 = 10 N at an angle ?1 = 45° counterclockwise from the positive x direction. The second child exerts a force of F2 = 6 N at an angle ?2 = 30° clockwise from the positive x direction. (A) Find the magnitude (in N) and direction of the friction force acting on the sled if it moves with constant velocity. magnitude = ? direction (counterclockwise from the +x-axis) = ? (B) What is the coefficient of kinetic friction between the sled and the ground? (C) What is the magnitude of the acceleration (in m/s2) of the sled if F1 is doubled and F2 is halved in magnitude?
The diagram below is a top-down view of two children pulling a 11.6-kg sled along the snow. The first child exerts a force of F1 = 10 N at an angle ?1 = 45° counterclockwise from the positive x direction. The second child exerts a force of F2 = 6 N at an angle ?2 = 30° clockwise from the positive x direction.
(A) Find the magnitude (in N) and direction of the friction force acting on the sled if it moves with constant velocity.
magnitude = ?
direction (counterclockwise from the +x-axis) = ?
(B) What is the coefficient of kinetic friction between the sled and the ground?
(C) What is the magnitude of the acceleration (in m/s2) of the sled if F1 is doubled and F2 is halved in magnitude?
We are given mass of sled. We are given forces acting on sled. We first find net force acting on sled. Since the sled is moving with constant velocity net force on it is zero. We hence find frictional force and then coefficient of friction. We then find acceleration of sled for new forces given.
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