The differential equation 5 dy – 14y = 0 has characteristic equation with roots d²y dx² help (numbers) Therefore there are two linearly independent solutions help (formulas) d²y dy +5- dx² dx - y(x) = = 0 help (formulas) Note: Enter the solutions as a comma separated list (they should be those usual exponential ones as in the book). Use these to solve the initial value problem 14y = 0, y(0) = −7, help (formulas) dy dx -(0) -2
The differential equation 5 dy – 14y = 0 has characteristic equation with roots d²y dx² help (numbers) Therefore there are two linearly independent solutions help (formulas) d²y dy +5- dx² dx - y(x) = = 0 help (formulas) Note: Enter the solutions as a comma separated list (they should be those usual exponential ones as in the book). Use these to solve the initial value problem 14y = 0, y(0) = −7, help (formulas) dy dx -(0) -2
Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
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ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
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Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...
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2.1.2. Ordinary
what would g(7) =?
![The differential equation 5 dy – 14y = 0 has characteristic
equation
with roots
help (numbers)
Therefore there are two linearly independent solutions
help (formulas)
Note: Enter the solutions as a comma separated list (they should be those
usual exponential ones as in the book).
Use these to solve the initial value problem
d²y dy
+5-
dx² dx
d²y
dx²
y(x) =
←
= 0 help (formulas)
14y = 0,
y(0) = −7,
help (formulas)
dy
dx
-(0)
-2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4d6d6ec3-8d2a-4662-b20e-640089acaa34%2F75d7e3d4-becd-4da1-bb1e-24a7e05eee21%2Fpo5x1sd_processed.png&w=3840&q=75)
Transcribed Image Text:The differential equation 5 dy – 14y = 0 has characteristic
equation
with roots
help (numbers)
Therefore there are two linearly independent solutions
help (formulas)
Note: Enter the solutions as a comma separated list (they should be those
usual exponential ones as in the book).
Use these to solve the initial value problem
d²y dy
+5-
dx² dx
d²y
dx²
y(x) =
←
= 0 help (formulas)
14y = 0,
y(0) = −7,
help (formulas)
dy
dx
-(0)
-2
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