The differential equation 5 dy – 14y = 0 has characteristic equation with roots d²y dx² help (numbers) Therefore there are two linearly independent solutions help (formulas) d²y dy +5- dx² dx - y(x) = = 0 help (formulas) Note: Enter the solutions as a comma separated list (they should be those usual exponential ones as in the book). Use these to solve the initial value problem 14y = 0, y(0) = −7, help (formulas) dy dx -(0) -2

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2.1.2. Ordinary Differential Equations

what would g(7) =? 

The differential equation 5 dy – 14y = 0 has characteristic
equation
with roots
help (numbers)
Therefore there are two linearly independent solutions
help (formulas)
Note: Enter the solutions as a comma separated list (they should be those
usual exponential ones as in the book).
Use these to solve the initial value problem
d²y dy
+5-
dx² dx
d²y
dx²
y(x) =
←
= 0 help (formulas)
14y = 0,
y(0) = −7,
help (formulas)
dy
dx
-(0)
-2
Transcribed Image Text:The differential equation 5 dy – 14y = 0 has characteristic equation with roots help (numbers) Therefore there are two linearly independent solutions help (formulas) Note: Enter the solutions as a comma separated list (they should be those usual exponential ones as in the book). Use these to solve the initial value problem d²y dy +5- dx² dx d²y dx² y(x) = ← = 0 help (formulas) 14y = 0, y(0) = −7, help (formulas) dy dx -(0) -2
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