The differential equation below models the temperature of a 94°C cup of coffee in a 24°C room, where it is known that the coffee cools at a rate of 1°C per minute when its temperature is 74°C. Solve the differential equation to find an expression for the temperature of the coffee at time t. (Let y be the temperature of the cup of coffee in °C, and let t be the time in minutes, with t = 0 corresponding to the time when the temperature was 94°C. dy/dt=-1/50(y-24) step 1. We have dy/dt=-1/50(y-24), which seperates to become dy=-1/50dt
The differential equation below models the temperature of a 94°C cup of coffee in a 24°C room, where it is known that the coffee cools at a rate of 1°C per minute when its temperature is 74°C. Solve the differential equation to find an expression for the temperature of the coffee at time t. (Let y be the temperature of the cup of coffee in °C, and let t be the time in minutes, with t = 0 corresponding to the time when the temperature was 94°C. dy/dt=-1/50(y-24) step 1. We have dy/dt=-1/50(y-24), which seperates to become dy=-1/50dt
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.7: Applications
Problem 13EQ
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The differential equation below models the temperature of a 94°C cup of coffee in a 24°C room, where it is known that the coffee cools at a rate of 1°C per minute when its temperature is 74°C. Solve the differential equation to find an expression for the temperature of the coffee at time t. (Let y be the temperature of the cup of coffee in °C, and let t be the time in minutes, with
t = 0 corresponding to the time when the temperature was 94°C.
dy/dt=-1/50(y-24)
step 1.
We have dy/dt=-1/50(y-24),
which seperates to become dy=-1/50dt
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