Question

Asked Feb 6, 2019

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The distance (in feet) of an object from a point is given by s(t) = t2, where time t is in seconds.

(a)

What is the average velocity of the object between t = 2 and t = 5?

(b)

By using smaller and smaller intervals around 2, estimate the instantaneous velocity at time t = 2.

Step 1

Given the distance of an object from an point at time t is given by equation s(t) = t^{2}, where t in seconds and distance in feet.

Average velocity can be calculated by dividing the distance travelled by the total time taken to travel that distance.

Step 2

we need to find the average velocity between t = 2 and t = 5. Here we get the distance travelled by the object in 2 seconds by substitution the value of t in the distacne finction s(t). Similarly we can calculate the distance travelled in 5 seconds by substituting the value of t is distance function s(t).

In 2 seconds obhect travels 4 feet and in 5 seconds object ...

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