The distance s between the planes is given by the formula, s = Vx2 + v². Thus, s? = x² + y?. One plane is 90 miles away and moving towards the point of convergence at 450 miles per hour so x = 90 dx and dt The other plane is 120 miles away and moving towards the point of convergence at 600 miles per hour, so y = dy 120 and dt

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.1: Equations
Problem 76E
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y
140
120
100
80
60아 y
40
20
X
20
40
60
80
100
The distance s between the planes is given by the formula, s = V x2 + v². Thus, s² = x² + y2.
One plane is 90 miles away and moving towards the point of convergence at 450 miles per hour so x = 90
dx
and
dt
= -
The other plane is 120 miles away and moving towards the point of convergence at 600 miles per hour, so y =
dy
120 and
dt
Transcribed Image Text:y 140 120 100 80 60아 y 40 20 X 20 40 60 80 100 The distance s between the planes is given by the formula, s = V x2 + v². Thus, s² = x² + y2. One plane is 90 miles away and moving towards the point of convergence at 450 miles per hour so x = 90 dx and dt = - The other plane is 120 miles away and moving towards the point of convergence at 600 miles per hour, so y = dy 120 and dt
Expert Solution
Step 1

The two planes are moving towards the point of convergence (0,0) which is the intersection of the x-axis and y-axis. As both the planes move, their distance from (0,0) will keep on reducing with passing time, so the rate of change of the distances x and y with respect to time will be both negative.

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