The ends of a "parabolic" water tank are the shape of the region inside the graph of y = x2 for 0 s ys 4; the cross sections parallel to the top of the tank (and the ground) are rectangles. At its center the tank is 4 feet deep and 4 feet across. The tank is 7 feet long. Rain has filled the tank and water is removed by pumping it up to a spout that is 5 feet above the top of the tank. Set up a definite integral to find the work W that is done to lower the water to a depth of 3 feet and then find the work. [Hint: You will need to integrate with respect to y.] W = (foot-pounds) symbolic formatting help

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 90E
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The ends of a "parabolic" water tank are the shape of the region inside the graph of y = x2 for 0 s y s 4; the cross sections parallel to the top of the tank (and the ground) are rectangles. At its
center the tank is 4 feet deep and 4 feet across. The tank is 7 feet long. Rain has filled the tank and water is removed by pumping it up to a spout that is 5 feet above the top of the tank. Set up a
definite integral to find the work W that is done to lower the water to a depth of 3 feet and then find the work. [Hint: You will need to integrate with respect to y.]
W =
(foot-pounds)
symbolic formatting help
Transcribed Image Text:The ends of a "parabolic" water tank are the shape of the region inside the graph of y = x2 for 0 s y s 4; the cross sections parallel to the top of the tank (and the ground) are rectangles. At its center the tank is 4 feet deep and 4 feet across. The tank is 7 feet long. Rain has filled the tank and water is removed by pumping it up to a spout that is 5 feet above the top of the tank. Set up a definite integral to find the work W that is done to lower the water to a depth of 3 feet and then find the work. [Hint: You will need to integrate with respect to y.] W = (foot-pounds) symbolic formatting help
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