The equation of the circle whose center lies in the first quadrant on the straight line y=2x, passes through the origin and has a radius of 5 units, is Select one: O a. x2+ y? +x+2y=0 O b. x2+y2 –x-2y=0 O c. x² +y² – 2x–4y=0 O d. x2+y² +2x+ 4y= 0

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.3: Hyperbolas
Problem 38E
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The equation of the circle whose center lies in the first quadrant on the straight line y=2x, passes through the origin and
has a radius of /5 units, is
Select one:
O a. x?+y² +x+2y=0
O b. x2+y2 –x-2y=0
а.
O C. x2+ y2 – 2x-4y=0
O d. x2+ y? +2x+4y=0
Transcribed Image Text:The equation of the circle whose center lies in the first quadrant on the straight line y=2x, passes through the origin and has a radius of /5 units, is Select one: O a. x?+y² +x+2y=0 O b. x2+y2 –x-2y=0 а. O C. x2+ y2 – 2x-4y=0 O d. x2+ y? +2x+4y=0
what is the value of a, such that the given limit is evaluated after applying L'Hopital's rule once
x- a sinhax
lim
x-0 x sinhx
Select one:
O a = -1
O a=0
O a# +1
O a = 1
Transcribed Image Text:what is the value of a, such that the given limit is evaluated after applying L'Hopital's rule once x- a sinhax lim x-0 x sinhx Select one: O a = -1 O a=0 O a# +1 O a = 1
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