The equivalent circuit of a 22KVA, 11700/520 V, 60HZ, single-phase loaded transformer when referred to its low-voltage side is given. Find the percent efficiency of this transformer under this loading conditions. 4=40.25/-22.5 = 40.25 1.0 + j1.25 2 Vp Vs = 4 K2 fj6.1 Ko 381 /0 v Select one: O a. %n = 84.23 % O b. None O c. %n = 89.5 % O d. %n = 95.33 %

The equivalent circuit of a 22KVA, 11700/520 V, 60HZ, single-phase loaded transformer when referred to its low-voltage side is given. Find the percent efficiency of this transformer under this loading conditions. 4=40.25/-22.5 = 40.25 1.0 + j1.25 2 Vp Vs = 4 K2 fj6.1 Ko 381 /0 v Select one: O a. %n = 84.23 % O b. None O c. %n = 89.5 % O d. %n = 95.33 %

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.27P: A three-phase transformer is rated 1000MVA,220Y/22kV. The Y-equivalent short-circuit impedance,...

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