The expression sin(arccos )

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.5: Product-to-sum And Sum-to-product Formulas
Problem 37E
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Can you please explain this a little more?
10:40
AA
A study.240tutoring.com
(L40
+ Return to course
The expression sin(arccos )
A
V25–x2
5
The arccos() = 0. Using
trigonometric ratios, the side adjacent
to 0 is x and the hypotenuse is 5. Next,
using the Pythagorean theorem, the
opposite side is v25 – x².
The ratio for sine is
opposite/hypotenuse which then gives
V25-x2
5
V25-2?
Continue
Correct
Transcribed Image Text:10:40 AA A study.240tutoring.com (L40 + Return to course The expression sin(arccos ) A V25–x2 5 The arccos() = 0. Using trigonometric ratios, the side adjacent to 0 is x and the hypotenuse is 5. Next, using the Pythagorean theorem, the opposite side is v25 – x². The ratio for sine is opposite/hypotenuse which then gives V25-x2 5 V25-2? Continue Correct
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