The expression y='s (1/c)^x   is equivalent to:   a) x= logc^y b) y= -(1/c)^y c) y=(c)^-x d) x= (1/c)^y

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter11: Exponential And Logarithmic Functions
Section11.5: Exponential Equations, Logarithmic Equations, And Problem Solving
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The expression y='s (1/c)^x   is equivalent to:

 

a) x= logc^y

b) y= -(1/c)^y

c) y=(c)^-x

d) x= (1/c)^y 

 

please provide steps, I don't just want the answer but want to understand why that is the answer as i am very confused on this concept. 

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