The f2e4t sec2e4t dt is {A} = = tan e 4t + C {B} = sec³e4t + C 16 {C} /e4t tan e4t + C {D} et sec³e4t + C

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.2: Trigonometric Equations
Problem 104E
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pls include solution with let u & du.
The 2e4t sec²e4t dt is
{A} = tan et + C
{B} sec³e4t + C
ܘܐ
4t
{C} {/e¹t tan ett + C
{D}=e4t sec³e4t + C
Transcribed Image Text:The 2e4t sec²e4t dt is {A} = tan et + C {B} sec³e4t + C ܘܐ 4t {C} {/e¹t tan ett + C {D}=e4t sec³e4t + C
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