The figure shows how a function f(x) and its linear approximation (i.e., its tangent line) change value when a changes from co to xo + da. Suppose f(x) = x² + 2x, xo = 1 and dx = 0.05. Your answers below need to be very precise, so use many decimal places. (a) Find the change Af = f(xo + da) - f(xo). Af=0 (b) Find the estimate (i.e., the differential) df = f'(ro) dx. df = (c) Find the approximation error | Af-df. Error = f(xo + dr) f(ro) Af = f(zo + dz)-f(zo) dz v=f(x) Error-Af-df Zo (Click on graph to enlarge) df-f(z)dz to + dz Tangent

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 18T
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The figure shows how a function f(x) and its linear approximation (i.e., its
tangent line) change value when a changes from co to xo + da.
Suppose f(x) = x² + 2x, xo = 1 and dx = 0.05. Your answers below need to
be very precise, so use many decimal places.
(a) Find the change Af = f(xo + dx) = f(xo).
Af=
(b) Find the estimate (i.e., the differential) df = f'(ro) dx.
df =
(c) Find the approximation error | Af -df.
Error =
f(ro+dr)
f(ro)
Af = f(xo+dz)-f()
FO
dz
y = f(x)
Error = Af-df
(Click on graph to enlarge)
df-f'(x)dz
Io + dz
Tangent
Transcribed Image Text:The figure shows how a function f(x) and its linear approximation (i.e., its tangent line) change value when a changes from co to xo + da. Suppose f(x) = x² + 2x, xo = 1 and dx = 0.05. Your answers below need to be very precise, so use many decimal places. (a) Find the change Af = f(xo + dx) = f(xo). Af= (b) Find the estimate (i.e., the differential) df = f'(ro) dx. df = (c) Find the approximation error | Af -df. Error = f(ro+dr) f(ro) Af = f(xo+dz)-f() FO dz y = f(x) Error = Af-df (Click on graph to enlarge) df-f'(x)dz Io + dz Tangent
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