the first quadrant bounded by the graphs of y = V16 – x², y = 0, andx = 0 is revolved about (a) the line x = 4 and (b) the line y = -4. Using the method of cylindrical shells, set up but do not evaluate an integral for the volume of the solid generated when the region Rin V = 2a(4 – x)V16 – x² dx V = 2m(4 + x)V16 – x² åx V = 2a(4 – x)(16 – x²) ảx 16 V = A(4 – x)V16 – x² åx (b) V = 2m(4 + y)V16 – y² ây 16 Ov = 2a(4 + y)/16 – y² dy 16 V = A(4 + y)/16 – y dy =7 – »(16 – y°) ày 2x(4

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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the first quadrant bounded by the graphs of y = V16 – x², y = 0, andx = 0 is revolved about (a) the line x = 4 and (b) the line
y = -4.
Using the method of cylindrical shells, set up but do not evaluate an integral for the volume of the solid generated when the region Rin
V =
2a(4 – x)V16 – x² dx
V =
2m(4 + x)V16 – x² åx
V =
2a(4 – x)(16 – x²) ảx
16
V =
A(4 – x)V16 – x² åx
(b)
V =
2m(4 + y)V16 – y² ây
16
Ov =
2a(4 + y)/16 – y² dy
16
V =
A(4 + y)/16 – y dy
=7 – »(16 – y°) ày
2x(4
Transcribed Image Text:the first quadrant bounded by the graphs of y = V16 – x², y = 0, andx = 0 is revolved about (a) the line x = 4 and (b) the line y = -4. Using the method of cylindrical shells, set up but do not evaluate an integral for the volume of the solid generated when the region Rin V = 2a(4 – x)V16 – x² dx V = 2m(4 + x)V16 – x² åx V = 2a(4 – x)(16 – x²) ảx 16 V = A(4 – x)V16 – x² åx (b) V = 2m(4 + y)V16 – y² ây 16 Ov = 2a(4 + y)/16 – y² dy 16 V = A(4 + y)/16 – y dy =7 – »(16 – y°) ày 2x(4
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