The first thing needed is a IP-addressing range to use in our network. Since this assignment is done in a laboratory setting, we don't have to comply to the RFC1918[2] standards of private IP-addressing. An IP address is written in the form shown in equation (2.1.1). x x grpl grp2 grp3 grp4 Y grpl grp2 grp3 grp4 where {x EZ | 0≤x≤255} We need however to take into consideration that the address range of 224.0.0.0/3 have been reserved, for amongst other thing multicast. Because of this, we will need to use another modulus-value on the first octet when we are generating a usable ip-address range. Start by creating your groups unique IP-address range using equation (2.1.2) where {x,y Z | 0≤x≤ 223,0 ≤ y ≤ 255} (2.1.2) Where each octet will be based on each group members birthday. Value X is calculated according to equation (2.1.3), and value Y is calculated according to equation (2.1.4). YY * MM + DD mod 223 YY * MM + DD mod 255 (2.1.1) X y. y grpl grp2 grp3 grp4 Before continue to the next part, answer the following item: 0/20 • What is the broadcast address of The fourth group in the IP-address should be set to 0. Finally we will start with a subnet mask of /20, and you will end up with an address range that looks like equation (2.1.5) your groups subnet? (2.1.3) (2.1.4) (2.1.5)
The first thing needed is a IP-addressing range to use in our network. Since this assignment is done in a laboratory setting, we don't have to comply to the RFC1918[2] standards of private IP-addressing. An IP address is written in the form shown in equation (2.1.1). x x grpl grp2 grp3 grp4 Y grpl grp2 grp3 grp4 where {x EZ | 0≤x≤255} We need however to take into consideration that the address range of 224.0.0.0/3 have been reserved, for amongst other thing multicast. Because of this, we will need to use another modulus-value on the first octet when we are generating a usable ip-address range. Start by creating your groups unique IP-address range using equation (2.1.2) where {x,y Z | 0≤x≤ 223,0 ≤ y ≤ 255} (2.1.2) Where each octet will be based on each group members birthday. Value X is calculated according to equation (2.1.3), and value Y is calculated according to equation (2.1.4). YY * MM + DD mod 223 YY * MM + DD mod 255 (2.1.1) X y. y grpl grp2 grp3 grp4 Before continue to the next part, answer the following item: 0/20 • What is the broadcast address of The fourth group in the IP-address should be set to 0. Finally we will start with a subnet mask of /20, and you will end up with an address range that looks like equation (2.1.5) your groups subnet? (2.1.3) (2.1.4) (2.1.5)
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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![The first thing needed is a IP-addressing range to use in our network. Since
this assignment is done in a laboratory setting, we don't have to comply to the
RFC1918[2] standards of private IP-addressing.
An IP address is written in the form shown in equation (2.1.1).
X
grpl grp2 grp3 grp4
X
grpl grp2 grp3 grp4
We need however to take into consideration that the address range of 224.0.0.0/3
have been reserved, for amongst other thing multicast. Because of this, we will
need to use another modulus-value on the first octet when we are generating a
usable ip-address range.
Start by creating your groups unique IP-address range using equation (2.1.2)
where {x,y EZ | 0≤x≤ 223,0 ≤ y ≤ 255} (2.1.2)
where {x EZ | 0≤x≤ 255}
Where each octet will be based on each group members birthday. Value X is
calculated according to equation (2.1.3), and value Y is calculated according to
equation (2.1.4).
YY * MM + DD mod 223
YY MM + DD
X
mod 255
grpl
(2.1.1)
The fourth group in the IP-address should be set to 0. Finally we will start with
a subnet mask of /20, and you will end up with an address range that looks like
equation (2.1.5)
Y Y
grp2 grp3 grp4
Before continue to the next part, answer the following item:
0 /20
. What is the broadcast address of your groups subnet?
(2.1.3)
(2.1.4)
(2.1.5)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe8260224-635c-426e-a960-28f2cf28de1f%2F8a2f7299-69c7-47c1-b330-4458fb006e03%2Ftw8q3yv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The first thing needed is a IP-addressing range to use in our network. Since
this assignment is done in a laboratory setting, we don't have to comply to the
RFC1918[2] standards of private IP-addressing.
An IP address is written in the form shown in equation (2.1.1).
X
grpl grp2 grp3 grp4
X
grpl grp2 grp3 grp4
We need however to take into consideration that the address range of 224.0.0.0/3
have been reserved, for amongst other thing multicast. Because of this, we will
need to use another modulus-value on the first octet when we are generating a
usable ip-address range.
Start by creating your groups unique IP-address range using equation (2.1.2)
where {x,y EZ | 0≤x≤ 223,0 ≤ y ≤ 255} (2.1.2)
where {x EZ | 0≤x≤ 255}
Where each octet will be based on each group members birthday. Value X is
calculated according to equation (2.1.3), and value Y is calculated according to
equation (2.1.4).
YY * MM + DD mod 223
YY MM + DD
X
mod 255
grpl
(2.1.1)
The fourth group in the IP-address should be set to 0. Finally we will start with
a subnet mask of /20, and you will end up with an address range that looks like
equation (2.1.5)
Y Y
grp2 grp3 grp4
Before continue to the next part, answer the following item:
0 /20
. What is the broadcast address of your groups subnet?
(2.1.3)
(2.1.4)
(2.1.5)
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