Question

Asked Jul 16, 2019

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The flow in a river can be modeled as a log-normal distribution. From the data, it was estimated that, the probability that the flow exceeds 821 cfs is 50% and the probability that it exceeds 100 cfs is 90%. Let X denote the flow in cfs in the river. What is the mean of log (to the base 10) of X? Please report your answer in 3 decimal places.

Step 1

Let *X* be the flow in a river which follows log normal distribution.

It is provided that, P(*X* > 821) = 0.50 and P(*X* > 100) = 0.90.

If *X* is log normal, then *Y* = log10(*X*) is norm...

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