The following data are the results from two test conducted on a single phase 1000 VA, 230/115 V, 50 Hz transformer. Open circuit test (on high voltage side): Voc=230 V, loc = 0.8 A, Poc = 80 W Short circuit test (on low voltage side): Vsc = 10 V, Isc = 8 A, Psc = 20 W Based on the results, determine; i) the impedance of the transformer referred to the low voltage side and sketch the approximated equivalent circuit. ii) the transformer's voltage regulation and efficiency at 0.85 power factor lagging.

The following data are the results from two test conducted on a single phase 1000 VA, 230/115 V, 50 Hz transformer. Open circuit test (on high voltage side): Voc=230 V, loc = 0.8 A, Poc = 80 W Short circuit test (on low voltage side): Vsc = 10 V, Isc = 8 A, Psc = 20 W Based on the results, determine; i) the impedance of the transformer referred to the low voltage side and sketch the approximated equivalent circuit. ii) the transformer's voltage regulation and efficiency at 0.85 power factor lagging.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

A 100 KVA, 6600/330 V, 50 Hz., single-phase transformer took 10 A and 436 watts at 100 V in a short-circuit test, the figures referring to the H.V. side. Calculate the voltage to be applied to the H.V. side on full load at power factor 0.8 lagging when the secondary terminal voltage is 330 V.
A 10kVA, 200/400V 50Hz single-phase transformer gave the following test results. O/C test: 200V, 1.3A, 120W, on l.v. side. S/C test: 22V, 30A, 200W on h.v. side. Calculate voltage drop of transformer. Voltage regulation? Efficiency of transformer?
Equivalent circuit parameters R1 = 1ohm, X1 = 2ohm R2 = 0.0035 ohm X2 = 0.0045ohm Xm = 1100ohm Rfe = 6400ohm primary voltage of a single-phase transformer in idle operation is 220 volts, secondary voltage is 11 volts. (Xm is magnetizing reactance, Rfe is iron resistance, values indicated by index 1 belong to primary side, values indicated by index 2 belong to secondary side) a. Calculate the secondary values reduced to primary. b. Calculate the idle running iron and magnetizing currents and the efficiency of the transformer in idle operation. c. Calculate the secondary voltage of the transformer and the active and reactive powers drawn from the secondary side by using the T equivalent circuit under conditions where the transformer is connected to the network where the voltage does not change and feeds a load of Zy = 0.5+ j0.3ohm.
2.An open circuit test was performed on a 150 kVA, 1200V/600V single phase transformer. Applying 600 V gave a wattmeter reading of 1000 W. Which of the following values can be derived from this result? A) The total resistance of the windings on the low voltage side is 360 ohms. B) The resistance of the core referred to the high voltage side is 360 ohms C) The resistance of the core referred to the low voltage side is 360 ohms D) THERE IS NO SOLUTION.
1- A 500-kVA, 3-phase, 50 Hz transformer has a voltage ratio (line voltages) of 66/33 kV and is delta/star connected. The resistances per phase are: high voltage 35 ©, low voltage 0.876 Q and the iron loss is 3050 W. Calculate the value of efficiency at full-load and one-half of full-load respectively (a) st unity pLand (6) 0.8 pE
A 5 kVA, 220/110 volts single-phase transformer was tested and has the following results. At short-circuit test with rated input current the power measured is 150 watts. At open circuit test, the power measured is 52 watts at rated input voltage. Determine: 1. the efficiency at 0.8 lagging power factor for the following loads: a. 1/4 of the rated b. rated c. 1.2 of the rated 2. the maximum efficiency
A 500-kVA, 3-phase, 50 Hz transformer has a voltage ratio (line voltages) of 33/11 kV and is delta/star connected. The resistances per phase are: high voltage 35 Q, low voltage 0.876 Q and the iron loss is 3050 W. Calculate the value of efficiency at full-load and one-half of full-load respectively (a) at unity pf and (b) 0.8 pf
A 50kVA 2300/230 V single-phase transformer has following test results:OC test: 230 V, 2 A, 359WSC test:80 V, rated current, 555W(a)Calculate efficiency and % voltage regulation at 80% of rated load at 0.8 PF lag.(b)Calculate maximum efficiency at 0.8 PF lag.
Q/ 30-kVA, 2200/220-V, 50-Hz distribution transformer is tested for efficiency and regulation as follows : O.C. test( Low voltage side ) : 220 V 4.2 A, 148 W S.C. test ( Low voltage side ) : 86 V 10.5 A, 360 W Efficiency at full-load and half the full-load at 0.8 p.f. lagging current. Equivalent reactance referred to primary & referred to secondary..........ohm , ..........ohm Equivalent resistance referred to primary & referred to secondary..........ohm , ..........ohm Regulation of transformer at 0.5 p.f. lagging current The magnetizing current and reactance component of no-load are.........amper , .........ohm The working current and resistance component of no-load are.........amper , .........ohm *
2) A 20 KVA, 2400/240 V, 60 Hz transformer, to Determine the equivalent circuit impedances. The data obtained from The open circuit and short circuit tests carried out on the primary side of the transformer are the following: Open circuit test VCA = 2400 V ICA = 0.20 A PCA = 50 W Short circuit test Vcc = 50 V Icc = 8.33 A PCC = 230 W a) Determine the equivalent circuit parameters of the transformer referred to the high voltage side. b) Find the transformer voltage regulation for conditions Nominal and F.P. 0.9 in delay.
19.A 25kVA, 2400/240, 60Hz single phase transformer gave the following short circuit test result Vsc = 100V, Isc = 10.41A, Psc = 116. Find the equivalent resistance in ohms referred to primary. Assume Ip rated is equal to Isc. round off answer to 4 decimal places if necessary.
A 75-KVA, 230-V/115-V, 60-Hz transformer was tested with the following results: Short-circuit test: 9.5 V, 326 A, 1200 W Open-circuit test: 115 V, 16.3 A, 750 W Determine the KVA load at maximum efficiency