The following formula gives the distance between two points, (x1, yl) and (x2, y2) in the Cartesian plane: Vin-n + (n - m)" Given the center and a point on the circle, you can use this formula to find the radius of the circle. Write a program that prompts the user to enter the x and y coordinates of the center and those of a point on the circle. The program should then output the cirele's radius and area by calling the following methods that you should define: a. distance: This method takes as its parameters four double values xl, yl.x2, and y2 representing the coordinates of two points in the plane and returns the distance between them, it actually returns the value of the radius. Header of distance method: public static double distancetdouble xl, double y1, double x2, deuble y2) 2/3 You can use Math sqrt and Math,pow methods b. area: This method takes as its parameter the radius of the cirele and returms the circle's area. Area of the circle = x* radius radius; for a use the value 3.14159 or the constant Math.PL. Header of area method: public static double areal double r) Sample Runi: Enter the coordinates of the center: 1 2 Enter the coordinates of a point on the circle: 4 7 The radius of the circle equals 5.830951894845301 The area of the circle equals 106.81415022205297
The following formula gives the distance between two points, (x1, yl) and (x2, y2) in the Cartesian plane: Vin-n + (n - m)" Given the center and a point on the circle, you can use this formula to find the radius of the circle. Write a program that prompts the user to enter the x and y coordinates of the center and those of a point on the circle. The program should then output the cirele's radius and area by calling the following methods that you should define: a. distance: This method takes as its parameters four double values xl, yl.x2, and y2 representing the coordinates of two points in the plane and returns the distance between them, it actually returns the value of the radius. Header of distance method: public static double distancetdouble xl, double y1, double x2, deuble y2) 2/3 You can use Math sqrt and Math,pow methods b. area: This method takes as its parameter the radius of the cirele and returms the circle's area. Area of the circle = x* radius radius; for a use the value 3.14159 or the constant Math.PL. Header of area method: public static double areal double r) Sample Runi: Enter the coordinates of the center: 1 2 Enter the coordinates of a point on the circle: 4 7 The radius of the circle equals 5.830951894845301 The area of the circle equals 106.81415022205297
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter6: User-defined Functions
Section: Chapter Questions
Problem 15PE
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Transcribed Image Text:The following formula gives the distance between two points, (x1, yl) and (x2, y2) in the
Cartesian plane:
Given the center and a point on the circle, you can use this formula to find the radius of the
circle. Write a program that prompts the user to enter the x and y coordinates of the center
and those of a point on the circle. The program should then output the cirele's radius and
area by calling the following methods that you should define:
a. distance: This method takes as its parameters four double values xl, yl.x2, and y2
representing the coordinates of two points in the plane and returns the distance
between them, it actually returns the value of the radius.
Header of distance method:
public static double distanceldouble xl, double yl, double s2, donuble y2)
2/3
You can use Math.sqrt and Math,.pow methods
b. area: This method takes as its parameter the radius of the circle and returns the
circle's area. Area of the circle = x* radius * radius; for a use the value 3.14159 or
the constant Math.PI.
Header of aren method:
public statie double areal(double r)
Sample Runl:
Enter the coordinates of the center: 1 2
Enter the coordinates of a point on the circle: 4 7
The radius of the circle equals 5.830951894845301
The area of the circle equals 10a6.81415022205297
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