The following incomplete code snippet: names ["Alice","Bob","Charlie"] scores = [15,5,10] winrates [0.25666655612748945, 0.34179143015027125, 0.4015420137222393] for i in range (len (names)): print (f"{names[i]:7| _}") Should produce this result: Alice |15|0.26 Bob |05|0.34 Charlie|10|0.40 What code needs to go in the blank?
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- #include <stdio.h> int arrC[10] = {0}; int bSearch(int arr[], int l, int h, int key); int *joinArray(int arrA[], int arrB[]) { int j = 0; if ((arrB[0] + arrB[4]) % 5 == 0) { arrB[0] = 0; arrB[4] = 0; } for (int i = 0; i < 5; i++) { arrC[j++] = arrA[i]; if (arrB[i] == 0 || (bSearch(arrA, 0, 5, arrB[i]) != -1)) { continue; } else arrC[j++] = arrB[i]; } for (int i = 0; i < j; i++) { int temp; for (int k = i + 1; k < j; k++) { if (arrC[i] > arrC[k]) { temp = arrC[i]; arrC[i] = arrC[k]; arrC[k] = temp; } } } for (int i = 0; i < j; i++) { printf("%d ", arrC[i]); } return arrC; } int bSearch(int arr[], int l, int h, int key) { if (h >= l) { int mid = l + (h - l) / 2; if…Create an iterator that returns numbers, starting with 1, and each sequence will increase by one (returning 1,2,3,4,5 etc.):For this C code, find the values of a, b, c and d that give hit = 1, and the result#include <stdio.h>#include <stdlib.h>void end_now();char *next_input(); int hash = 8765309;int INPUTS[4]; void phase03(){ // TODO: put numbers in input.txt to pass the code below int a; int b; int c; int d; int targ = 0; targ |= 1 << (hash % 13); targ = targ << (hash % 3); targ |= 1 << (hash % 19); targ = targ << (hash % 5); targ |= 1 << (hash % 31); targ = targ << (hash % 7); int shot = 0; shot |= 1 << a; shot |= 1 << b; shot |= 1 << c; shot |= 1 << d; int hit = shot ^ targ; hit = !hit; if(hit){ printf("Right on target: nice shootin' bitslinger!\n"); return; } printf("Shifty bits hit? Xor not it seems...\n"); end_now();}
- In Python, grades = {'Tim': [87,96,70], 'Sue': [100,87,90], 'Jack': [94,77,90], 'Kevin': [100,81,82], 'Bart': [83, 65, 85]} Ask user to enter the names of the rows, i.e., indices. You can use: len(grades) to get the number of rows of the DataFrame. In addition, using the sort_index() method, ask user whether they wish to sort by rows or by columns and whether to sort in ascending or descending order (do not use any if-else statements) '''In java, please read the text file as array. Then, replace the null with 0 and calculate the sum of the new students in ABC University.Example of text file: (university,year,total_students,new_students,new_staff,ABC, 2000, 3457, , ,ABC, 2001, 3675,218, ,EFG, 2000, 2389,602, ,EFG, 2001, 2785,396, 65,)Finish the code about the CircleTest.cpp. #include <gtest/gtest.h>#include "pch.h"#include <math.h># define M_PI 3.141592653589793238462643383279502884L /* pi */ class Circle {private: double radius;public: void set_radius(double); double area(); double perimeter();}; void Circle::set_radius(double r) { radius = r;}double Circle::area() { return M_PI * radius * radius;}double Circle::perimeter() { return 2 * M_PI * radius;} TEST(Area, AreaIsCorrect){ Circle circ; circ.set_radius(3); EXPECT_DOUBLE_EQ(circ.area(), 3 * 3 * M_PI); } int main(int ac, char* av[]){ testing::InitGoogleTest(&ac, av); return RUN_ALL_TESTS();}
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- The two-dimensional arrays m1 and m2 are identical if theyhave the same contents. Write a method that returns true if m1 and m2 are identical,using the following header:public static boolean equals(int[][] m1, int[][] m2)Write a test program that prompts the user to enter two 3 x 3 arrays of integers and displays whether the two are identical. Here are the sample runs: Enter list1: 51 25 22 6 1 4 24 54 6Enter list2: 51 22 25 6 1 4 24 54 6The two arrays are identicalEnter list1: 51 5 22 6 1 4 24 54 6Enter list2: 51 22 25 6 1 4 24 54 6The two arrays are not identicalbriefly comment the code#include <stdio.h>#include <stdlib.h>/* ADJACENCY MATRIX int source,V,E,time,visited[20],G[20][20];void DFS(int i){int j;visited[i]=1;printf(" %d->",i+1);for(j=0;j<V;j++){if(G[i][j]==1&&visited[j]==0)DFS(j);}}int main(){int i,j,v1,v2;printf("\t\t\tGraphs\n");printf("Enter the no of edges:");scanf("%d",&E);printf("Enter the no of vertices:");scanf("%d",&V);for(i=0;i<V;i++){for(j=0;j<V;j++)G[i][j]=0;}/* creating edges :P */for(i=0;i<E;i++){printf("Enter the edges (format: V1 V2) : ");scanf("%d%d",&v1,&v2);G[v1-1][v2-1]=1; } for(i=0;i<V;i++){for(j=0;j<V;j++)printf(" %d ",G[i][j]);printf("\n");}printf("Enter the source: ");scanf("%d",&source);DFS(source-1);return 0;}String spell = "Redikulus"; How would you find the index of the 'u' just before the last 's' using a single line of code? Multiple answers may be correct. Given the string String spell = "Redikulus"; How would you find the index of the 'u' just before the last 's' using a single line of code? Multiple answers may be correct. A. spell.substring(5, spell.length()).indexOf('u'); B. spell.indexOf('u', 5); C. spell.lastIndexOf('u'); D. spell.contains('u'); E. spell.indexOf('u', spell.length() - 2); F. spell.indexOf('u', spell.indexOf('l'));