The force F (in newtons) of a hydraulic cylinder in a press is proportional to the square of sec x where x is the distance (in meters) that the cylinder Is extended in its cycle. The domaln of F Is [0, 1/3], and F(0) = 100. (a) Find F as a function of x. F(x) = (b) Find the average force exerted by the press over the interval [0, n/3]. (Round your answer to one decimal place.) F = Need Help? Read It Master It

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.7: More On Inequalities
Problem 44E
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The force F (in newtons) of a hydraulic cylinder in a press is proportional to the square of sec x where x is the distance (in meters) that the cylinder is extended in its cycle. The domaln of
F Is [0, 1/3], and F(0) = 100.
(a) Find F as a function of x.
F(x) =
(b) Find the average force exerted by the press over the interval [0, n/3]. (Round your answer to one decimal place.)
F =
N
Need Help?
Read It
Master It
Transcribed Image Text:The force F (in newtons) of a hydraulic cylinder in a press is proportional to the square of sec x where x is the distance (in meters) that the cylinder is extended in its cycle. The domaln of F Is [0, 1/3], and F(0) = 100. (a) Find F as a function of x. F(x) = (b) Find the average force exerted by the press over the interval [0, n/3]. (Round your answer to one decimal place.) F = N Need Help? Read It Master It
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