Show step by step solution asap I will rate Positively . The four forces and geometry shown. The resultant force in x direction is:FBD at AT₁To30°75°150° A500 lb6045°Te1) (TB+ Tp cos 150° - Tc cos 60° sin 45°) i2) (TB + Tp cos 150° + Tccos 60° sin 45°) i3) (TB + Tp cos 150° - Tc cos 60° cos 45°) iO4) (TB + TD cos 150° + Tc cos 60° cos 45º) i

According to the given data We need to find Resulting fore in the x-direction

The four forces and geometry shown. The resultant force in x direction is: FBD at A To 75° 150° 30° 500 lb 60 45° Tc +Tp cos 150°-Tc cos 60° sin 45°) i 2) (TB + TD cos 150° + Tc cos 60° sin 45°) i 3) (TB + Tp cos 150° - Tc cos 60° cos 45°) i 4) (TB + TD cos 150° + Tc cos 60° cos 45°) i

The four forces and geometry shown. The resultant force in x direction is: FBD at A To 75° 150° 30° 500 lb 60 45° Tc +Tp cos 150°-Tc cos 60° sin 45°) i 2) (TB + TD cos 150° + Tc cos 60° sin 45°) i 3) (TB + Tp cos 150° - Tc cos 60° cos 45°) i 4) (TB + TD cos 150° + Tc cos 60° cos 45°) i

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter1: Introduction To Statics

Section: Chapter Questions

Problem 1.48P: The pole OB is subjected to the 6004b force at B. Determine (a) the rectangular components of the...

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