The frame shown is supported by a shear pin (diameter, d, ultimate shear Tu in ksi) and by a tie-rod AB (diameter dr =0.625 inches and yield stress Oy in ksi). Both the tie-rod and the pin are to be sized with a factor of safety of FS = N (see table), the tie-rod with respect to ultimate shear failure. platform load, Wallowable. See table to complete calculations of the required W. (40 pts) Determine the allowable Ultimate Yield DIAMETER, Factor of Stress, Tu stress, L1 L2 L3 d in inches Safety, N in ksi Oy in Ksi 0.65 50 50 2.8 2.75 ft 2.75ft 4.00ft dp View a-a of C a A

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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The frame shown is supported by a shear pin
(diameter, d, ultimate shear tu in ksi) and by a tie-rod AB (diameter dr
=0.625 inches and yield stress Oy in ksi). Both the tie-rod and the pin
are to be sized with a factor of safety of FS = N (see table), the tie-rod
with respect to ultimate shear failure.
platform load, Wallowable. See table to complete calculations of the
required W. (40O pts).
Determine the allowable
Ultimate
Yield
DIAMETER,
Factor of
Stress, Tu
stress,
L1
L2
L3
d in inches
Safety, N
in ksi
Oy in Ksi
0.65
50
50
2.8
2.75 ft
2.75ft
4.00ft
dp
View a-a ofC
B
LI
a
Lz-
Transcribed Image Text:The frame shown is supported by a shear pin (diameter, d, ultimate shear tu in ksi) and by a tie-rod AB (diameter dr =0.625 inches and yield stress Oy in ksi). Both the tie-rod and the pin are to be sized with a factor of safety of FS = N (see table), the tie-rod with respect to ultimate shear failure. platform load, Wallowable. See table to complete calculations of the required W. (40O pts). Determine the allowable Ultimate Yield DIAMETER, Factor of Stress, Tu stress, L1 L2 L3 d in inches Safety, N in ksi Oy in Ksi 0.65 50 50 2.8 2.75 ft 2.75ft 4.00ft dp View a-a ofC B LI a Lz-
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