The front face of a tent is triangular and the height of the triangle is two-thirds of the base. The length of the tent is 3 ft more than the base of the triangular face. If the tent holds a volume of 108 ft3, determine its dimensions. x + 3

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A: See solution below

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A: Let the width= x yd So the length = (x+5) yd

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A: Given length(l)=(6)width(w) Perimeter(p)=140ft

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Q: . The front face of a tent is triangular and the height of the triangle is two-thirds of the base.…

A: Consider the given:  The objective is the find the dimensions of the tent:  Base = xHeight =…

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A: Find the dimensions

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A: Let width of rectangle be ' a '

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A: From the given data:

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A: