the function returns the result as a string if the expression is legal. the expression returns an empty string and then put the function public class Ez1MathEval { public String heavywtEval (String exprn) { return "" } }
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the function returns the result as a string if the expression is legal. the expression returns an empty string and then put the function
public class Ez1MathEval {
public String heavywtEval (String exprn) {
return ""
}
}
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- In the class String, the substring method inserts a String into another String. -True or -FalseA string object is ______ which means its contents cannot be changed. Select one: a. Absolute b. Immutable c. Undisputable d. IrreversibleFix all the errors in the code // Program displays some facts about a string public classDebugSeven3 { public static void main(String[] args) { String quote = "Honesty is the first chapter in the book of wisdom. - Thomas Jefferson"; System.out.println("index.of('f') is: " + quoteindexOf('f')); System.out.println("index.of('x') is: " + quoteindexOf('x')); System.out.println("char.At(5) is: " + quote.charAt(50)); System.out.println("endsWith(\"daughter\") is: " + quote.endsWith("daughter")); System.out.println("endsWith(\"son\") is: " + quote.endsWith("son")); System.out.println("replace('e', '*') is: ", quote.replace('e', '*')); } }
- Write a function findFirstUpper() that takes a string as parameter, finds returns the index of the first uppercase letter in the string. If there is no uppercase letter in the string, then the function will return -1.Example: Function call findFirstUpper("best course is CS104!") will return 15 (index of the 'C').Example: Function call findFirstUpper("good morning!") will return -1 CODEE:PYTHONcapCount.py make a program called capCount.py that has a function that takes in a string and prints the number of capital letters in the first line, then prints the sum of their indices in the second line. The string "hEllo, World" would should look like this: 28Write a function that counts the occurrences of a word in a string. Thefunction should return an integer. Do not assume that just one space separates words and a string can contain punctuation. Write the function sothat it works with either a String argument or a StringBuilder object.
- Instructions: In the code editor, you are provided with a main() function that asks the user for a string and passes this string and the size of this string to a function call of the function, preserveString(). This preserveString() function has the following description: Return type - void Name - preserveString Parameters The string Length of the string Description - this is a recursive function that prints the string repeatedly. Each time it prints the string, it excludes the last character of the string until only one character is left. This preserveString() function has already been partially implemented. Your only task is to add the recursive case of this function. Please Finish the code ASAP: This is my current given code: #include<stdio.h>#include<string.h> #define STR_MAX_SIZE 100 void preserveString(char*, int); int main(void) { char str[STR_MAX_SIZE]; printf("Enter string: "); fgets(str, STR_MAX_SIZE, stdin); preserveString(str,…The countSubstring function will take two strings as parameters and will return an integer that is the count of how many times the substring (the second parameter) appears in the first string without overlapping with itself. This method will be case insensitive. For example: countSubstring(“catwoman loves cats”, “cat”) would return 2 countSubstring(“aaa nice”, “aa”) would return 1 because “aa” only appears once without overlapping itself. public static int countSubstring(String s, String x) { if (s.length() == 0 || x.length() == 0) return 1; if (s.length() == 1 || x.length() == 1){ if (s.substring(0,1).equals(x.substring(0,1))){ s.replaceFirst((x), " "); return 1 + countSubstring(s.substring(1), x); } else { return 0 + countSubstring(s.substring(1), x); } } return countSubstring(s.substring(0,1), x) + countSubstring(s.substring(1), x); } public class Main { public static void main(String[] args) { System.out.println(Recursion.countSubstring("catwoman loves cats","cat"));…Consider the following application. Identify and correct any syntactic errors or omissions by rewriting the line number and the corrected line. Note: There are 8 lines with errors. Each line may have multiple errors. Here’s an example (here, the error is on line 2, the correction is in bold – int x = 0;): 01 public static void main(String[] args){ 02 int x = '0'; 02 int x = 0; 03 int y + x = 7 03 int y = x + 7; 04 } 01 public Class Average; 02 { 03 public void main(String [] args) 04 { 05 double sc = (70, 75, 90, 83, 85, 97, 82, 79, 94, 87; 06 double me su = 0.0 07 for (int k = 0; k < sc.length(); k++); 08 su += sc[ ]; 09 double me = su/sc.length() 10 System.Out.printf("Output: %.2f" + me); 11 } 12 } What value of the variable me will be printed in line 10?
- Write a function findFirstUpper() that takes a string as parameter, finds returns the index of the first uppercase letter in the string. If there is no uppercase letter in the string, then the function will return -1.Example: Function call findFirstUpper("best course is CS104!") will return 15 (index of the 'C').Example: Function call findFirstUpper("good morning!") will return -1. CODEEE:PYTHON PLEASEwrite the following as a function that takes in a string and returns a string. for (int i=0; i != user_string. size(); i++){ if (islower(user_string[i])){ user_string[i]=toupper(user_string[i]); } elseif(isupper(user_string[i])){ user_string[i]=tolower(user_string[i]); } } cout<<user_string; return0; }Function Name: compliments Parameters: answer1 - a boolean (True or False) representing whether the user is "smart" answer2 - a boolean (True or False) representing whether the user is "awesome" answer3 - a boolean (True or False) representing whether the user is "fun" Description: Write a function that outputs a string of compliments based on the adjectives selected by the inputs. Use the inputs True and False. The function should return the string “You are” concatenated with the compliments that are true. The three compliments should be: "smart" "awesome" and "fun". If none of the compliments are true, print the string “Goodbye.” instead. Test Cases: >>>compliments(True, True, True) You are smart awesome fun. >>>compliments(False, True, False) You are awesome. >>>compliments(False, False, False) Goodbye.