The general solution of (D²+2D+1)(D²+4)y=0 @ -+Ceª A y=(C,+Cx)e*+C;e B none of the given choices © y=(c,+Cx)e*+C+c¢* -2x D y=(C,+Cr)e=+C,cos2r + C sin2x ® y=(C,+Cx)e*+C,cos2r + C ,sin2x

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter13: Conic Sections
Section13.1: Circles
Problem 48PS
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The general solution of (D²+2D +1)(D²+4)y=0 is
B none of the given choices
© y=(c,+c)e*+ce-"+C¢"
D y=(C,+Cx)e=*+C,cos2x + C sin2x
y=(C,+Cx)e*+C,cos2r + C ,sin2x
Transcribed Image Text:The general solution of (D²+2D +1)(D²+4)y=0 is B none of the given choices © y=(c,+c)e*+ce-"+C¢" D y=(C,+Cx)e=*+C,cos2x + C sin2x y=(C,+Cx)e*+C,cos2r + C ,sin2x
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