The German mathematician Karl Weierstrass (1815-1897) noticed that the substitution t = tan(x/2) will convert any rational function of sin(x) and cos(æ) into an ordinary rational function of t. If t = tan(x/2), -T < x < T, then it can be shown that sin () - 1 cos V1+ t2 V1+t? 1 t2 2t cos(x) sin(æ) 1+t2 ' 1+t2 and 2 -dt. 1+t? dx = Use the substitution given above to transform the following integral into a rational function of t and then evaluate the integral: 7/2 1+ sin(x) dx - cos(x T/3

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter3: Polynomial And Rational Functions
Section: Chapter Questions
Problem 11T: Consider the following rational functions: r(x)=x2x22x1 s(x)=x2+4x3+27 t(x)=x+2x39x u(x)=x225x2+x6...
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The German mathematician Karl Weierstrass (1815-1897) noticed that the substitution t = tan(x/2) will convert any rational function of sin(x) and cos(x)
into an ordinary rational function of t. If t = tan(x/2), –T < x < T, then it can be shown that
1
t
CoS
sin
1+t²
V1+t?
1- t2
2t
cos(x)
sin(x)
1+t2 '
1+t2 '
and
2
dt.
1+t?
dx =
Use the substitution given above to transform the following integral into a rational function of t and then evaluate the integral:
7/2
-3
dx
1+ sin(x) – cos(x)
T/3
Transcribed Image Text:The German mathematician Karl Weierstrass (1815-1897) noticed that the substitution t = tan(x/2) will convert any rational function of sin(x) and cos(x) into an ordinary rational function of t. If t = tan(x/2), –T < x < T, then it can be shown that 1 t CoS sin 1+t² V1+t? 1- t2 2t cos(x) sin(x) 1+t2 ' 1+t2 ' and 2 dt. 1+t? dx = Use the substitution given above to transform the following integral into a rational function of t and then evaluate the integral: 7/2 -3 dx 1+ sin(x) – cos(x) T/3
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