import java.util.Scanner;import java.util.InputMismatchException;public class NameAgeChecker { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); String inputName; int age; inputName = scnr.next(); while (!inputName.equals("-1")) { // FIXME: The following line will throw an InputMismatchException. // Insert a try/catch statement to catch the exception. age = scnr.nextInt(); System.out.println(inputName + " " + (age + 1)); inputName = scnr.next(); } }} The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. Theprogram fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catchstatement to catch java.util.InputMismatch Exception, and output 0 for the age.Ex: If the input is:Lee 18Lua 21Mary Beth 19.Stu 33-1then the output is:Lee 19Lua 22Mary 0Stu 34

In this question we need to update given Java code so that it catches input mismatch exception and…

The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catch statement to catch java.util.Input MismatchException, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33. -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34

The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catch statement to catch java.util.Input MismatchException, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33. -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter14: Exception Handling

Section: Chapter Questions

Problem 1PE

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The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18Lua 21Mary Beth 19Stu 33-1 then the output is: Lee 19Lua 22Mary 0Stu 34 #include <string>#include <iostream> using namespace std; int main(int argc, char* argv[]) { string inputName; int age; // Set exception mask for cin stream cin.exceptions(ios::failbit); cin >> inputName; while(inputName != "-1") { // FIXME: The following line will throw an ios_base::failure. // Insert a try/catch statement to catch the exception. // Clear cin's failbit to put cin in a useable state. cin >> age; cout << inputName << " " << (age + 1) << endl;…
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 √
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34
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