The graph of f', the derivative of the differentiable function f, consists of five linear segments and a semi circle and is shown in the figure above. The functions f and f' are defined on the closed interva [-5, 10]. It is known that f(6) = -1. AB3: Find the minimum value of f on the closed interval - 5 ≤ x ≤ 10. Justify your answer..
The graph of f', the derivative of the differentiable function f, consists of five linear segments and a semi circle and is shown in the figure above. The functions f and f' are defined on the closed interva [-5, 10]. It is known that f(6) = -1. AB3: Find the minimum value of f on the closed interval - 5 ≤ x ≤ 10. Justify your answer..
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter6: Applications Of The Derivative
Section6.CR: Chapter 6 Review
Problem 48CR
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![4 f'(x)
3
2
TA
-5 -4 -3 -2 -1 0
1
7 8 9 10 11
-1
-2
AB4: Evaluate
The graph of f', the derivative of the differentiable function f, consists of five linear segments and a
semi circle and is shown in the figure above. The functions f and f' are defined on the closed interval
[-5, 10]. It is known that f(6) = -1.
AB3: Find the minimum value off on the closed interval - 5 ≤ x ≤ 10. Justify your answer..
The minimum value of f is f(6)=-1
[*13f" (3 + 2x) - 41]dx
x
= 2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F66d30f65-22c6-47d5-b371-c8d8c2d2b3f2%2Fd34be688-db74-426d-99a0-3a6e12985016%2Fwyhwjmd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4 f'(x)
3
2
TA
-5 -4 -3 -2 -1 0
1
7 8 9 10 11
-1
-2
AB4: Evaluate
The graph of f', the derivative of the differentiable function f, consists of five linear segments and a
semi circle and is shown in the figure above. The functions f and f' are defined on the closed interval
[-5, 10]. It is known that f(6) = -1.
AB3: Find the minimum value off on the closed interval - 5 ≤ x ≤ 10. Justify your answer..
The minimum value of f is f(6)=-1
[*13f" (3 + 2x) - 41]dx
x
= 2
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