The graph of the implicit equation x2+3xv+4v² = 1 is shown here with lines indicating where the tangent is horizontal (brown), vertical (green) and slope = -1 (red). Find the function representing the brown line by setting the numerator of dy/dx equal to zero and solving for y = Substitute this into the original equation and solve for the TOP point where the brown

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
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ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
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Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...
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The graph of the implicit equation y2+3xV+4v² = 1 is shown here with lines indicating where the tangent is horizontal (brown),
vertical (green) and slope = -1 (red). Find the function representing the brown line by setting the numerator of dy/dx equal to zero and
solving for y =
Substitute this into the original equation and solve for the TOP point where the brown
line intersects the curve, (
) (rounded to two decimal places).
-1
1
Transcribed Image Text:The graph of the implicit equation y2+3xV+4v² = 1 is shown here with lines indicating where the tangent is horizontal (brown), vertical (green) and slope = -1 (red). Find the function representing the brown line by setting the numerator of dy/dx equal to zero and solving for y = Substitute this into the original equation and solve for the TOP point where the brown line intersects the curve, ( ) (rounded to two decimal places). -1 1
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