The graphs below are for a spring-mass system. The same mass & spring were used for each graph. Fill in the table below the graphs. pos (m) 0.8 0.7 0.6 POSITION vs. TIME GRAPH #1 0.5 5 10 15 20 25 30 35 40 45 50 time uncertainty = 14 st X uncertainty of average period = 2.8 s Graph #1 Graph #2 Graph #3 Amplitude (m) X 18 x 8 14 to (s) X t (s) 48 45 pos (m) 0.8 0.7 0.6 0.5 POSITION vs. TIME GRAPH #2 t10 (s) M^^^^ˇˇˇˇˇˇˇˇ LA 5 10 15 20 25 30 35 40 45 50 uncertainty of average period time uncertainty 5 x Your answer is too high. 46 At for 10 cycles (s) 40 t (s) average T (s) pos (m) 0.8 0.7 0.6 POSITION vs. TIME GRAPH #3 0.5 5 10 15 20 25 30 35 40 45 50 Presumably, the average periods that you calculated are, within uncertainties, the same. This verifies that the period is independent of the amplitude. t (s)
The graphs below are for a spring-mass system. The same mass & spring were used for each graph. Fill in the table below the graphs. pos (m) 0.8 0.7 0.6 POSITION vs. TIME GRAPH #1 0.5 5 10 15 20 25 30 35 40 45 50 time uncertainty = 14 st X uncertainty of average period = 2.8 s Graph #1 Graph #2 Graph #3 Amplitude (m) X 18 x 8 14 to (s) X t (s) 48 45 pos (m) 0.8 0.7 0.6 0.5 POSITION vs. TIME GRAPH #2 t10 (s) M^^^^ˇˇˇˇˇˇˇˇ LA 5 10 15 20 25 30 35 40 45 50 uncertainty of average period time uncertainty 5 x Your answer is too high. 46 At for 10 cycles (s) 40 t (s) average T (s) pos (m) 0.8 0.7 0.6 POSITION vs. TIME GRAPH #3 0.5 5 10 15 20 25 30 35 40 45 50 Presumably, the average periods that you calculated are, within uncertainties, the same. This verifies that the period is independent of the amplitude. t (s)
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The graphs below are for a spring-mass system. The same mass & spring were used for each graph. Fill in the table below the graphs.
uncertainty of average period = time uncertainty/ 5
Transcribed Image Text:The graphs below are for a spring-mass system. The same mass & spring were used for each graph. Fill in the table below the graphs.
pos (m)
0.8
0.7
0.6
POSITION vs. TIME GRAPH #1
0.5
5 10 15 20 25 30 35 40 45 50
time uncertainty = 14 s
X
uncertainty of average period = 2.8 s
Graph #1
Graph #2
Graph #3
Amplitude
(m)
X 18
8
14
to
(s)
X
t(s)
48
45
pos (m)
0.8
0.7
0.6
0.5
POSITION vs. TIME GRAPH #2
t10
(s)
LAN
5 10 15 20 25 30 35 40 45 50
X
Your answer is too high.
46
www
uncertainty of average period = time uncertainty
5
At for 10 cycles
(s)
40
X 4
average T
(s)
t(s)
X
pos (m)
0.8
0.7
0.6
POSITION vs. TIME GRAPH #3
0.5
5 10 15 20 25 30 35 40 45 50
Presumably, the average periods that you calculated are, within uncertainties, the same. This verifies that the period is independent of the amplitude.
t(s)
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