The graphs of y = f(x) (solid) and y = g(x) (dashed) are shown. The two graphs intersect at (15, 18).Region 1(15,18)1915Region 2x = 19Suppose the area of Region 1 is 30 and the area of Region 3 is 11.Find the following.15[¹ (9(x) – ƒ(x)) dx =(f(x) — 9(x)) dx = |Region 319[ (g(x) – f(x)) dx =My = f(x)y = g(x)

Ques 1 ∫015gx-fxdx This integration result in area of REGION 1. Hence answer is 11.

The graphs of y = f(x) (solid) and y = g(x) (dashed) are shown. The two graphs intersect at (15, 18). Region 1 Region 2 15 ™ (9(x) – f(x) dx = (15, 18) x = 19 Suppose the area of Region 1 is 30 and the area of Region 3 is 11. Find the following. 19 19 * (ƒ(2) – 9(2)) dx = [ (g(x) — ƒ(2)) da Region 3 = y = f(x) y = g(x)

The graphs of y = f(x) (solid) and y = g(x) (dashed) are shown. The two graphs intersect at (15, 18). Region 1 Region 2 15 ™ (9(x) – f(x) dx = (15, 18) x = 19 Suppose the area of Region 1 is 30 and the area of Region 3 is 11. Find the following. 19 19 * (ƒ(2) – 9(2)) dx = [ (g(x) — ƒ(2)) da Region 3 = y = f(x) y = g(x)

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

ChapterA: Appendix

SectionA.2: Geometric Constructions

Problem 10P: A soda can has a volume of 25 cubic inches. Let x denote its radius and h its height, both in...

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