The initially stationary 30-kg block is subjected to the time-varying horizontal force whose magnitude Pis shown in the plot. Note that the force is zero for all times greater than 8 s. Determine the time t, at which the block comes to rest. P,N 322 30 kg HA-0.55 H, 0.77 8 Answer: t,-
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- The 600-lb cable spool is placed on a frictionless spindle that has been driven into the ground. If the force required to start the spool rotating is F = 160 lb, determine the coefficient of friction between the ground and the spool. Neglect the diameter of the spindle compared to the diameter of the spool.The conveyor belt is moving downward at 5 m/s. If the coefficient of static friction between the conveyor and the 15-kg package Bis * mu_{x} = 0.62 , determine the shortest time the belt can stop so that the package does not slide on the beltThe coefficient of static and kinetic friction between the 100 kg block and the inclined plane are 0.30 and 0.20, respectively. Determine the(a) the friction with the magnitude of 200 N to the block at rest, (b) the force P required to initiate motion up the incline from rest, and (c) the friction force F acting on the block if P=600N
- If the force exerted on cable AB by the motor is F = ( 110 t 3/2 ) N, where tt is in seconds, determine the 55-kg crate's velocity when ttt = 5 s . The coefficients of static and kinetic friction between the crate and the ground are μs = 0.37 and μk = 0.29, respectively. Initially the crate is at rest. (Figure 1)the 3-kg collar shown has a coefficient of kinetic friction uk=0.22 with the shaft. the spring is unstretched when s=0 and the collar is given an initial velocity of v0=19.5 m/s. the unstretched length of the spring is d=1.5m and the spring constant is k=597 N/m. What is the speed of the collar afer it has moved 1.5m?The conveyor belt is moving downward at 5 m/s. If the coefficient of static friction between the conveyor and the 12-kg package B is uk = 0.71, determine the shortest time the belt can stop so that the package does not slide on the belt.
- The spring has a stiffness k = 750 N/m and an unstretched length of 50 cm. A 2 kg block is given a speed vA (2 m/s when it is at A, and it slides down the incline having a coefficient of kinetic friction uk = 0.3. Determine the velocity of the block before it touches the spring, the work done by the weight and the friction.The 2.4-Mg car increases its speed uniformly from rest to 22 m/s in 38 s up the inclined road. (a) Determine the maximum power that must be supplied by the engine, which operates with an efficiency of ϵ = 0.8. Express your answer with the appropriate units. (b) Also, find the average power supplied by the engine. Express your answer with the appropriate units. Please use watts, not Mw for the final answer. Answer is not 38280 W and 18105.2 W.The force P is applied to the 48-kg block when it is at rest. Determine the magnitude and direction of the friction force exerted by the surface on the block if (a) P = 0, (b) P = 229 N, and (c) P = 354 N. (d) What value of P is required to initiate motion up the incline? The static and kinetic coefficients of friction between the block and the incline are μs = 0.34 and μk = 0.30, respectively. The friction force is positive if up the incline, negative if down the incline.
- The crate, which has a mass of 140 kg, is subjected to the action of the three forces shown in the figure. If it is originally at rest, determine the friction force when Py =750 N, P, =900 N, P;=500Nand 6 = 259 Assume the coefficient of kinetic friction between the crate and the surface is pi = 0.40.If the system starts from rest, Figure 1. Determine the velocities of each block, and the tension in the rope, when block C has descended 10 meters, on the inclined plane. mB = 75 kg, mC = 400 kg, and the coefficient of friction between block C and the plane is 0.2A 20-lb block slides down a 30° inclined plane with an initial velocity of 2 ft/s. Determine the velocity of the block in 3 s if the coefficient of kinetic friction between the block and the plane is U k = 0.25.