The interval of convergence of the series E t0 (n+1)(x+3)n %3D1 is equal to: (n+2) ]- 4; -2] [-4; -2] This option This op tion [-4; -2[ 1- 4; –2[

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.3: Geometric Sequences
Problem 49E
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The interval of convergence of the series E
t0 (n+1)(x+3)n
%3D1
(n+2)
is equal to:
]- 4; -2]
[-4; -2]
This option
This op tion
[-4; -2[
1- 4; -2[
Transcribed Image Text:The interval of convergence of the series E t0 (n+1)(x+3)n %3D1 (n+2) is equal to: ]- 4; -2] [-4; -2] This option This op tion [-4; -2[ 1- 4; -2[
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