The inverse forms of the results in Problem 49 in Exercises 7.1 are et cos bt x^{(5-507² +6²) and b x^² { * is − a)² + b² y(t). sin bt. Use the Laplace transform and these inverses to solve the given initial-value problem. y' + y = est cos 4t, y(0) = 0

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Chapter1: Functions And Models
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The inverse forms of the results in Problem 49 in Exercises 7.1 are
s-8
x^² { (5-5²3) ² + b ².
and
= eat cos bt
b
- -
-
-6²} et sin bt.
1 (sa)² +6²)
Use the Laplace transform and these inverses to solve the given initial-value problem.
y' + y = est cos 4t, y(0) = 0
y(t) =
Transcribed Image Text:The inverse forms of the results in Problem 49 in Exercises 7.1 are s-8 x^² { (5-5²3) ² + b ². and = eat cos bt b - - - -6²} et sin bt. 1 (sa)² +6²) Use the Laplace transform and these inverses to solve the given initial-value problem. y' + y = est cos 4t, y(0) = 0 y(t) =
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