Now, 2 x (+) dt 2 50, d2x(+) dt 2 -1 d2x(1) dt 2 is +2 J2x(+) ct 2 + 1 +2 = -15(++ 2) + 25 (1-0) + 15 (t-1) = -√(x + 2) + 251€) + 5 (+-2) By using differentiation in time domain property, the fourier tram form is jw2 (jw) ² x 1w) = -1.e م لم + 2 + +2+ How did he get the inside the circle
Now, 2 x (+) dt 2 50, d2x(+) dt 2 -1 d2x(1) dt 2 is +2 J2x(+) ct 2 + 1 +2 = -15(++ 2) + 25 (1-0) + 15 (t-1) = -√(x + 2) + 251€) + 5 (+-2) By using differentiation in time domain property, the fourier tram form is jw2 (jw) ² x 1w) = -1.e م لم + 2 + +2+ How did he get the inside the circle
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter5: Inner Product Spaces
Section5.5: Applications Of Inner Product Spaces
Problem 91E
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Transcribed Image Text:Now, 2 x (+) is
dt 2
50,
d2x(+)
dt 2
d2x(1)
dt 2
2
G
+2
d2x(+)
at 2
= -15(+ + 2) + 25 (1-0) + 15 (t-1)
-S(+2) + 25H) + 5 (1-2)
By using differentiation in time domain property,
the fourier framform is
(jw) ² x 1w) = -1.e
+ 1
jw2
+2
20 لم +2 +
How did he get the
value inside the circle
ni
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