Question

Asked Jan 17, 2019

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the length of a rectangle is a two digit number with identical digits (aa). the width is 1/10 of the length. the perimeter is 2 times the area of the rectangle. find the length and width

Step 1

Given the length of the rectangle is two digit number with same digits aa. As a is in units place and tens place we can write length of the rectangle as 11a.

The width of the rectangle is one by tenth of the length so width is (11a/10).

Step 2

Here the formulas of area and perimeter of rectangle are mentioned and the length and width values we have are plugged in. We can see the final equations after simplification.

Step 3

Here the given constraint is twice the area of rectangle is equal to perimeter of rectan...

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