The lengths of tables sold at various furniture stores follow anormal distribution with u =120 cm and o= 15.6 cm.a) Find the probability that a single randomly selected tableis less than 123.6 cm.P(X < 123.6) =b) You intend to draw a random sample of size n = 27tables. Calculate the standard error of the sample mean:0x =c) Find the probability that a sample of size n = 27randomly selected tables has a mean length less than 123.6cm.P(x< 123.6) =Enter your answers as numbers accurate to 4 decimal places.Answers obtained using exact z-scores or z-scores rounded to3 decimal places are accepted.

From the provided information, Mean (µ) = 120 Standard deviation (σ) = 15.6 X~N (120, 15.6)

The lengths of tables sold at various furniture stores follow a normal distribution with u = 120 cm and σ = 15.6 cm. a) Find the probability that a single randomly selected table is less than 123.6 cm. P(X < 123.6) = = 27 b) You intend to draw a random sample of size n tables. Calculate the standard error of the sample mean: ox c) Find the probability that a sample of size n = 27 randomly selected tables has a mean length less than 123.6 cm. P(x < 123.6) =

The lengths of tables sold at various furniture stores follow a normal distribution with u = 120 cm and σ = 15.6 cm. a) Find the probability that a single randomly selected table is less than 123.6 cm. P(X < 123.6) = = 27 b) You intend to draw a random sample of size n tables. Calculate the standard error of the sample mean: ox c) Find the probability that a sample of size n = 27 randomly selected tables has a mean length less than 123.6 cm. P(x < 123.6) =

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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