The lifetime of an electronic deivce is modeled as an exponential random variable. If (10+I)% of the devices have a mean of 20,000 hours and the remaining devices have a mean of 50,000 hours, what proportion of the devices will fail before 60,000 hours?

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A: given  α=0.05β=0.025∆=550-525=25σ=80

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A: It is an important part of statistics . It is widely used .

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A: Given Data: T~ Exponential (1/5)   a) To Find: P(T>8) P(T>8)=1-P(T<8)=1-(1-e-15×8)=0.2019

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A: Hi! Thank you for the question As per the honour code, We’ll answer the first question since the…

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A: It is an important part of statistics. It is widely used.

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A: Answer:-  Given, μ = 30

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