The limiting capacity of the habitat of a wildlife herd is 800. The growth rate of the herd is proportional to the unutilized opportunity for growth, as described by the differential equation dN/dt=k(800-N). The general solution of this differential equation is N=800-Ce^(-kt). When t=0, the population of the herd is 130. After 2 years, the population has grown to 190. A. Write the population N as a function t. B. What is the population of the herd after 5 years?
The limiting capacity of the habitat of a wildlife herd is 800. The growth rate of the herd is proportional to the unutilized opportunity for growth, as described by the differential equation dN/dt=k(800-N). The general solution of this differential equation is N=800-Ce^(-kt). When t=0, the population of the herd is 130. After 2 years, the population has grown to 190. A. Write the population N as a function t. B. What is the population of the herd after 5 years?
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.7: Applications
Problem 16EQ
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The limiting capacity of the habitat of a wildlife herd is 800. The growth rate of the herd is proportional to the unutilized opportunity for growth, as described by the differential equation dN/dt=k(800-N). The general solution of this differential equation is N=800-Ce^(-kt). When t=0, the population of the herd is 130. After 2 years, the population has grown to 190.
A. Write the population N as a function t.
B. What is the population of the herd after 5 years?
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