The line tangent to the graph of g(x) = x³ – 4x +1 at the point (2, 1) is given by the formula L(x) = 8(x – 2) +1. These functions are graphed below. 10 F1

Algebra & Trigonometry with Analytic Geometry
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Chapter4: Polynomial And Rational Functions
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The line tangent to the graph of g(x) = x³ – 4x + 1 at the point (2, 1) is given by the formula
L(x) = 8(x – 2) + 1.
These functions are graphed below.
10
F1
-10
Transcribed Image Text:The line tangent to the graph of g(x) = x³ – 4x + 1 at the point (2, 1) is given by the formula L(x) = 8(x – 2) + 1. These functions are graphed below. 10 F1 -10
Which of the following statements are true? Select all that apply.
O A. The functions are approximately equal on the interval 0.5 < x < 1.0.
O B. The functions are approximately equal on the interval 1.9 < < 2.1.
O C. The graphs intersect at the point (2, 1).
D. The functions have the same y-intercept.
E. The slope of the line equals g'(2).
OF. The slope of the line equals g (0).
O G. None of the above are true.
Transcribed Image Text:Which of the following statements are true? Select all that apply. O A. The functions are approximately equal on the interval 0.5 < x < 1.0. O B. The functions are approximately equal on the interval 1.9 < < 2.1. O C. The graphs intersect at the point (2, 1). D. The functions have the same y-intercept. E. The slope of the line equals g'(2). OF. The slope of the line equals g (0). O G. None of the above are true.
Expert Solution
Step 1

To select: The correct options.

Given: The function is g(x)=x3-4x+1 and the line tangent to the graph at the point (2,1) is Lx=8x-2+1.

Concept used:

If the line is y=mx+b then m is the slope and b is the y-intercept.

The slope of the function  at x=a is g'(a).

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