The load voltage waveform has the mean value of a half sinewave, namely * 2( Vmax)/pi ( Vmax)/2pi O ( Vmax)/pi O 2( Vmax)/2pi

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.23P: A single-phase source has a terminal voltage V=1200volts and a currentI=1530, which leaves the...
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The load voltage waveform has the mean
value of a half sinewave, namely *
2( Vmax)/pi
O (Vmax)/2pi
( Vmax)/pi
O 2( Vmax)/2pi
Analysis of the load-voltage waveform
gives a mean value of *
O (Vmax)/2pi
O 2( Vmax)*(1+cos alph)
( Vmax)/2pi(1+cos alph)
O 2( Vmax)/2pi(1+cosalph)
Transcribed Image Text:The load voltage waveform has the mean value of a half sinewave, namely * 2( Vmax)/pi O (Vmax)/2pi ( Vmax)/pi O 2( Vmax)/2pi Analysis of the load-voltage waveform gives a mean value of * O (Vmax)/2pi O 2( Vmax)*(1+cos alph) ( Vmax)/2pi(1+cos alph) O 2( Vmax)/2pi(1+cosalph)
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