The Maclaurin series for f(x) = cos(x) is x² (-1)" (x) 2n (2n)! 1- 2! n=0 T(x) = By transforming the series for cos(x), find the Maclaurin series f(x) = cos(-4x). (Your terms should be entered from smallest degree to highest degree.) Written compactly, this series is: T(x) = = + 00 n=0 4! 6! +

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.3: Geometric Sequences
Problem 44E
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The Maclaurin series for f(x)
(-1)" (x) 2n
(2n)!
x²
1-
2!
n=0
T(x)
Written compactly, this series is:
T(x) =
=
+
By transforming the series for cos(x), find the Maclaurin series f(x) = cos(-4x).
(Your terms should be entered from smallest degree to highest degree.)
00
n=0
cos(x) is
4! 6!
+
Transcribed Image Text:The Maclaurin series for f(x) (-1)" (x) 2n (2n)! x² 1- 2! n=0 T(x) Written compactly, this series is: T(x) = = + By transforming the series for cos(x), find the Maclaurin series f(x) = cos(-4x). (Your terms should be entered from smallest degree to highest degree.) 00 n=0 cos(x) is 4! 6! +
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